(w-1)^2=2w^2-5w-27

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Solution for (w-1)^2=2w^2-5w-27 equation:



(w-1)^2=2w^2-5w-27
We move all terms to the left:
(w-1)^2-(2w^2-5w-27)=0
We get rid of parentheses
-2w^2+(w-1)^2+5w+27=0
We add all the numbers together, and all the variables
-2w^2+5w+(w-1)^2+27=0
We move all terms containing w to the left, all other terms to the right
-2w^2+5w+(w-1)^2=-27

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